第一節 平衡常數與轉化率
平衡常數與轉化率之間的計算

對於任意可逆反應:

\[a\text{A}\left( \text{g} \right)\ +\ b\text{B}\left( \text{g} \right)\ \rightleftharpoons \ c\text{C}\left( \text{g} \right)\ +\ d\text{D}\left( \text{g} \right)\]

在一定溫度下,向體積為 \(\text{V}\ \text{d}{{\text{m}}^{\text{3}}}\) 的密閉容器內通入 \(p\ \text{mol}\ \text{A}\left( \text{g} \right)\) 和 \(q\ \text{mol}\ \text{B}\left( \text{g} \right)\)。達至平衡後,測得 \(\text{A}\left( \text{g} \right)\) 的轉化率是 \(x\)。根據指引,完成下表中的計算,並總結平衡常數 \({{K}_{\text{c}}}\) 的表達式。

\(a\text{A}\left( \text{g} \right)\ + \) \( b\text{B}\left( \text{g} \right)\ \ \ \) \(\rightleftharpoons \) \( c\text{C}\left( \text{g} \right)\ + \) \( d\text{D}\left( \text{g} \right)\)
起始摩爾數 \(\left( \text{mol} \right)\) \(p\) \(q\) \(0\) \(0\)
摩爾數改變 \(\left( \text{mol} \right)\)
\(-px\)
\(\displaystyle{-\frac{b}{a}px}\)
\(\displaystyle{+\frac{c}{a}px}\)
\(\displaystyle{+\frac{d}{a}px}\)
平衡摩爾數 \(\left( \text{mol} \right)\)
\(p\left( 1-x \right)\)
\(\displaystyle{q\ -\frac{b}{a}px}\)
\(\displaystyle{\frac{c}{a}px}\)
\(\displaystyle{\frac{d}{a}px}\)
平衡濃度 \(\left( \text{mol}\ \text{d}{{\text{m}}^{-3}} \right)\)
\(\displaystyle{\frac{p\left( 1-x \right)}{\text{V}}}\)
\(\displaystyle{\frac{q\ -\ \displaystyle{\frac{b}{a}px}}{\text{V}}}\)
\(\displaystyle{\frac{\displaystyle{\frac{c}{a}px}}{\text{V}}}\)
\(\displaystyle{\frac{\displaystyle{\frac{d}{a}px}}{\text{V}}}\)
平衡常數
\[\displaystyle{{{K}_{\text{c}}}\ =\ \frac{{{\left( \displaystyle{\frac{\displaystyle{\frac{c}{a}px}}{\text{V}}} \right)}^{c}}{{\left( \displaystyle{\frac{\displaystyle{\frac{d}{a}px}}{\text{V}}} \right)}^{d}}}{{{\left[ \displaystyle{\frac{p\left( 1-x \right)}{\text{V}}} \right]}^{a}}{{\left( \displaystyle{\frac{q-\displaystyle{\frac{b}{a}px}}{\text{V}}} \right)}^{b}}}}\]
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